2/(3x^2/3)=1/9

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Solution for 2/(3x^2/3)=1/9 equation: 


D( x )

(3*x^2)/3 = 0

(3*x^2)/3 = 0

(3*x^2)/3 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2/((3*x^2)/3) = 1/9 // - 1/9

2/((3*x^2)/3)-(1/9) = 0

2/((3*x^2)/3)-1/9 = 0

2*x^-2 = 1/9 // : 2

x^-2 = 1/18

-2 < 0

1/(x^2) = 1/18 // * x^2

1 = 1/18*x^2 // : 1/18

18 = x^2

x^2 = 18 // ^ 1/2

abs(x) = 3*2^(1/2)

x = 3*2^(1/2) or x = -(3*2^(1/2))

x in { 3*2^(1/2), -(3*2^(1/2)) }

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